Three capacitors of same capacitance are connected in parallel. When they are connected to a cell of 2 volt, total charge of 1.8µC is accumulated on them. Now they are connected in series and then charged by the same cell. The total charge stored in them will be
Text Solution
Verified by ExpertsThe correct answer is:
D
q 1 + q 2 + q 3 + = 1.8 µC = (3C)2 = 1.8 µC
C = 0.3µF
C eq = 
= 0.1 µF
Q = C eq V = 0.1 x 2 = 0.2 µC
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